A light ray is reflected and refracted at a water- interface, as shown in the fi

Question

A light ray is reflected and refracted at a water- interface, as shown in the figure. Find the reflection angle theta_r and refraction angle theta_b. In the figure below, there ia s current in the straight wire going from right to left. If the current is decreasing, what is the direction of the induced current in the round coil? (A) Clockwise (B) Counter-clockwise (C) Cannot be determined A hemispherical surface with radius r in a region of uniform electric field E has its axis aligned parallel to the direction of the field. The electric flux through the surface is (A) 0; (B) pir^2E; (C)4pir^2E; (D)2pir^2E An extended object is placed in front of a flat mirror and an image of the object is formed by the mirror. Which of the following statements is a correct? (A) The image is erect. (B) The image is a virtual image. (C) The image is reversed left and right. (D) The image has the same size as the object.

Explanation / Answer

Problem 1

angle of incidence = angle of reflection,

So 600 = r

or r = 600

Using Snell's law at the water glass interface we have;

sin600/sinb = 1.52/1.33

or sinb = 1.33sin600/1.52

or b = 49.270

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Problem 2

The changing current induces a changing flux through the loop. The flux is decreasing/weakening as the current is decreasing. So, as per Lenz's law, the current would be induced in the loop is such a direction so as to strengthen the flux. So the current would be induced in the loop in a counter-clockwise direction which will add up to the original induced field (which is out of page) and sternghten the flux.

hence,option B is correct.

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This concludes the answers. Check the answer and let me know if it's correct. If you need any more clarification or correction, feel free to ask.....

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