A 508.0-nm light source illuminates two slits with a separation of 6.00 times 10

Question

A 508.0-nm light source illuminates two slits with a separation of 6.00 times 10^-4 m, forming an interference pattern on a screen placed 3.90 m away from the slits. At a point a distance of 3.90 mm from the central maximum, what are the following? (a) the phase difference between the two waves originating at the slits (Give your answer to at least three significant figures.) (b) the intensity compared to that of the central maximum your response differs from the correct answer by more than 10%. Double check your calculations. I_max

Explanation / Answer

(a)

for phase difference we first need to calculate the path difference,

path difference= x d/D

path differnce=3.9x10-3 (6x10-4)/3.9

path difference=6x10-7 m

phase difference = (2 / )* path difference

phase difference=( 2/508x10-9) * 6x10-7

phase difference=7.417 radians.

(b)

for intensity,

i=io cos2(phase diff/2) where io is maximum intensity

i/io=cos2 (7.421/2)

i/io=0.71145

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