A. Two point charges were previously 18.0 cm apart. Then they were moved so that

Question

A. Two point charges were previously 18.0 cm apart. Then they were moved so that the force on each has become three times what it was before. How far apart are the charges now? b. A point charge (q_1 = +2e) is located at (0, 0). Another point charge (q_2 = -3e) is located at (-2, 0). A third point charge (q_3 = -6e) is located at (3, 0). Find the direction of the total electrical force exerted on q_1 c. Let q > 0 and d > 0. A particle with charge^+q is stationary and located at the point (0, d). A particle with charge -q is stationary and located at the point (0, -d). In which direction would an electron accelerate if it were located at (L, 0), where L > 0? d. Evaluate (T/F/N) the following statement. Justify your answer fully with any valid mix of words, drawings and calculations. "Three protons are located in the x-y plane: q_A is at (0, 0); q_B is at (1, 0); q_c is at (0, d). If the net force on q_A is in the 150 degree direction (angle measured conventionally), then d almostequalto -132.

Explanation / Answer

a) F = kq^2/r^2

Let the new distance be r'

F1* 3 = F2

kq^2/r^2 *3 = kq^2/r'^2

(r'/r)^2 = 1/3

r' = r/(3)^0.5 = 18/(3)^0.5 = 10.4 cm

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