A doctor examines a mole with a 15-cm focal length magnifying glass held 14.5 cm

Question

A doctor examines a mole with a 15-cm focal length magnifying glass held 14.5 cm from the mole. Randomized Variables d_o = 14.5 cm What is the image distance for this configuration in meters? Numeric A numeric value is expected and not an expression. d_i =__________ What is its magnification? Numeric A numeric value is expected and not an expression. m = _______ How big is the image of a 5.00 mm diameter mole in millimeters? Numeric A numeric value is expected and not an expression. h_i = ______

Explanation / Answer

object distance d0 = 14.5 cm

focal length f = 15 cm

-------------------

part(a)

image distance di = ?

fromlens expression

1/d0 + 1di = 1/f

1/14.5 + 1/di = 1/15

di = -435 cm

image distance di = 435 cm <<<<------------answer

===========================

part(b)

magnification m = -di/do = 435/14.5 = 30 <<<<<---------answer

--------------------

part (c)

magnification m = hi/ho

hi size of the image

ho = size of the object

hi/5 = 30

hi = 150 mm <<<<<<---------answer

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.