A golf ball is dropped from a height of h_1 = 3.7 m above the ground. After it b

Question

A golf ball is dropped from a height of h_1 = 3.7 m above the ground. After it bounces it only reaches a height, h_2 = 2.16 m above the ground. The golf hall has mass m = 0.1175 kg. Randomized Variables h_1 = 3.7 m h_2 = 2.16 m m = 0.1175 kg What is the magnitude of the impulse t in kilogram meters per second, the golf hall experienced during the bounce? If the golf ball was in contact with the ground for t = 0.154 s. what was the magnitude of the constant force F acting on it, in newtons? How much energy, in joules, did the golf ball transfer to the environment during the bounce?

Explanation / Answer

a)

Impulse imparted, I = m*(sqrt(2g*h1) - sqrt(2*g*h2))

So, I = 0.1175*(sqrt(2*9.8*3.7) + sqrt(2*9.8*2.16))

= 1.765 kg.m/s

b)

Force, F = I/t = 1.765/0.154 = 11.5 N

c)

energy transferred, U = 0.5*m*( (2*g*h1) - (2*g*h2))

= mg*(h1- h2)

= 0.1175*9.8*(3.7 - 2.16)

= 1.77 J

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