A uniform, 274-N rod that is 1.86 m long carries a 225-N weight at its right end
ID: 1549416 • Letter: A
Question
A uniform, 274-N rod that is 1.86 m long carries a 225-N weight at its right end and an unknown weight Wtoward the left end (see the figure (Figure 1) ). When Wis placed 54.2 cm from the left end of the rod, the system just balances horizontally when the fulcrum is located 77.3 cm from the right end.
Part A
Find W.
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Part B
If W is now moved 26.1 cm to the right, how far must the fulcrum be moved to restore balance?
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Part C
If W is now moved 26.1 cm to the right, in what direction must the fulcrum be moved to restore balance?
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Figure 1 of 1
A uniform, 274-N rod that is 1.86 m long carries a 225-N weight at its right end and an unknown weight Wtoward the left end (see the figure (Figure 1) ). When Wis placed 54.2 cm from the left end of the rod, the system just balances horizontally when the fulcrum is located 77.3 cm from the right end.
Part A
Find W.
W = NSubmitMy AnswersGive Up
Part B
If W is now moved 26.1 cm to the right, how far must the fulcrum be moved to restore balance?
x = mSubmitMy AnswersGive Up
Part C
If W is now moved 26.1 cm to the right, in what direction must the fulcrum be moved to restore balance?
If is now moved 26.1 to the right, in what direction must the fulcrum be moved to restore balance? to the left to the rightSubmitMy AnswersGive Up
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Figure 1 of 1
225 NExplanation / Answer
Balancing moment of arm from fulcrum
274 (93-77.3) + W ( 186-131.5) = 225(77.3)
4301.8 + W(54.5) = 17392.5
W = 240.196 N
b) let fulcrum be at "x" cm from right end.
240.196 (186 - 80.3 - x) + 274 ( 99-x) = 225 (x)
240.196 ( 105.7-x) + 27126 - 274x = 225x
25388.7172 - 240.196 x + 27126 = 499x
52514.7172= 739.196 x
x= 71.04 cm
3) to the right
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