A 1500 kg car drives at the bottom of a through with an effective radius of 80 m
ID: 1549228 • Letter: A
Question
Explanation / Answer
Writing equations of motion for the car at the trough
N-mg = m*a
a is the centripetal accelaration = v^2/R
then Normal force N = mg + (m*v^2/R)
N = (1500*9.8)+(1500*20^2/80)
N = 22200 N
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.