A small wooden block with mass 0.700 kg is suspended from the lower end of a lig

Question

A small wooden block with mass 0.700 kg is suspended from the lower end of a light cord that is 1.68 m long. The block is initially at rest. A bullet with mass 0.0136 kg is fired at the block with a horizontal velocity v_0. The bullet strikes the block and becomes embedded in it. After the collision the combined object swings on the end of the cord. When the block has risen a vertical height of 0.800 m, the tension in the cord is 5.00 N What was the initial speed v_0 of the bullet? Express your answer with the appropriate units.

Explanation / Answer

step;1

Given that

mass of the bullet m=0.0136 kg

mass of the wooden block M=0.7 kg

height h=0.8 m

initial velocity of wooden block u2=0 m/s

step;2

now we find the initial velocity of the bullet

initial velocity of bullet u={m+M/m}(2gh)^1/2

={0.0136+0.7/0.0136}(2*9.8*0.8)^1/2

=52.5*3.96

=207.9 m/s

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