Long, long ago, on a planet far, far away, a physics experiment was carried out.

Question

Long, long ago, on a planet far, far away, a physics experiment was carried out. First, a 0.210-kg ball with zero net charge was dropped from rest at a height of 1.00 m. The ball landed 0.350 s later. Next, the ball was given a net charge of 7.60 C and dropped in the same way from the same height. This time the ball fell for 0.630 s before landing. What is the electric potential at a height of 1.00 m above the ground on this planet, given that the electric potential at ground level is zero? (Air resistance can be ignored.) Answer is in V.

Explanation / Answer

From the given question,

mass(m)= 0.210kg

height(h)=1m

initial velocity(u)=0 m/s

time(t1)=0.350

s= ut + 1/2 at2

a=g( acceleration due to gravity)

1= 1/2 g (.35)2

g=16.32 m/s2

A charged body experiencies force in external electric field. As the time has increased, the force due to electric field acts in opposite ditection.

s= ut + 1/2 at2 ; u=0,

1= 1/2 a (0.63)2

a=5.04

mg-qE=ma

mg- qV/d= ma

m(g-a)= qV/d

md(g-a)/q= V

0.210* 1(16.32 - 5.04)/(7.6 x 10-6)=V

V=311684 V

Electric potential at height is approx 312 kV.

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