A 1200-kg SUV is moving along a straight highway at 12.0 m/s . Another car, with

Question

A 1200-kg SUV is moving along a straight highway at 12.0 m/s . Another car, with mass 1800 kg and speed 20.0 m/s , has its center of mass 40.0 m ahead of the center of mass of the SUV (Figure 1) .

Part A

Find the position of the center of mass of the system consisting of the two cars.

Express your answer using three significant figures.

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Part B

Find the magnitude of the system’s total momentum, by using the given data.

Express your answer to three significant figures and include the appropriate units.

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Part C

Find the speed of the system’s center of mass.

Express your answer to three significant figures and include the appropriate units.

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Part D

Find the system’s total momentum, by using the speed of the center of mass.

Express your answer to three significant figures and include the appropriate units.

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Part E

Compare your results of parts B and D.

Compare your results of parts B and D.

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Figure 1 of 1

A 1200-kg SUV is moving along a straight highway at 12.0 m/s . Another car, with mass 1800 kg and speed 20.0 m/s , has its center of mass 40.0 m ahead of the center of mass of the SUV (Figure 1) .

Part A

Find the position of the center of mass of the system consisting of the two cars.

Express your answer using three significant figures.

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Part B

Find the magnitude of the system’s total momentum, by using the given data.

Express your answer to three significant figures and include the appropriate units.

xcm = m behind the leading car

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Part C

Find the speed of the system’s center of mass.

Express your answer to three significant figures and include the appropriate units.

P1 =

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Part D

Find the system’s total momentum, by using the speed of the center of mass.

Express your answer to three significant figures and include the appropriate units.

vcm,x =

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Part E

Compare your results of parts B and D.

Compare your results of parts B and D.

P2 =

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P1 > P2 P1 < P2 P1 = P2

Figure 1 of 1

1200 kg 12.0 m/s ke 400 m 1800 kg 20.0 m/s

Explanation / Answer

a) let the center of mass of yellow car = 0

x = ( 1200 )(0) + ( 1800 )(40)/ ( 3000) = 24 m

b) Total magnitude= 1200 (12) + 1800 (20 ) =50400 kg m/s

c) speed of center of mass = 1200 x 12 + 1800x 20 / 3000 = 16.8 m//s

d)total momentum pf system = 3000 x 16.8 = 50400 kgm/s

e) P1= P2

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