PLEASE SOLVE ALL MULTIPLE CHOICES The displacement of an object for a round trip

Question

PLEASE SOLVE ALL MULTIPLE CHOICES

The displacement of an object for a round trip between two locations is always greater than zero. is always less than zero. is zero. can be greater than or less than but not equal to zero. A displacement vector R vector = xi + yj; the magnitude and orientation of its velocity vector is are given by |dR/dt| = squareroot (dx/dt)^2 - (dy/dt)^2 and theta = tan^-1 y/x respectively |dR/dt| = squareroot (dx/dt)^2 + (dy/dt)^2 and theta = tan^-1 x/y respectively |dR/dt| = squareroot (dx/dt)^2 + (dy/dt)^2 and theta = tan^-1 y/x respectively |dR/dt| = squareroot (dx/dt)^2 + (dy/dt)^2 + 2 dx/dt dy/dt and theta = tan^-1 x/y respectively At the highest point of a projectile the x-velocity changes from positive to negative the y-velocity is changing directions from upwards to downwards has zero-velocity None of the above The horizontal velocity of a projectile is constant all the time is decreasing due to the gravitational acceleration is increasing due to the acceleration

Explanation / Answer

1.

iii) always zero

since the object comes back to same location , hence displacement = 0

2.

ii)

since v = dx/dt i^ + dy/dt j^

magnitude = sqrt((dx/dt)2 + (dy/dt)2)

3

iii)

the velocity in y-direction becomes zero and object returns back

4.i)

constant all the time

since there is no acceleration along x-direction

5 iii)

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