A circular coil of insulated wire has a radius of 9.0 cm and contains 60 turns.

Question

A circular coil of insulated wire has a radius of 9.0 cm and contains 60 turns. You can assume that, unlike the solenoid, all turns of the coil are in the same plane. The ends of the wire are connected in series with a 15-Ohm resistor closing the circuit. The normal to the loop is initially parallel to a constant magnetic field of 5.0 times 10^-2 T. If the loop is flipped over, so that the direction of the normal is reversed, a pulse of current will flow through the resistor. What amount of charge will flow through the resistor? Assume that the resistance of the wire is negligible compared to that of the resistor.

Explanation / Answer

magnetic flux = N*B*A

indced emf e = rate of change in flux

e = N*B*A/t

current I = e/R

I = N*B*A/(R*t)

charge flowing Q = I*t

Q = N*B*A/R

Q = 60*5*10^-2*pi*0.09^2/15

Q = 0.0051 C <<<<<=====answer

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