A circular coil of copper wire is lying flat on a horizontal table. A bar magnet

Question

A circular coil of copper wire is lying flat on a horizontal table. A bar magnet is held with its south pole downward, vertically above the center of the coil. The magnet is released from rest and falls toward the coil. As viewed from above, you can say that, as it falls, the magnet induces counterclockwise current in the loop. clockwise current in the loop. no current in the loop. an emf but no electric current in the loop. Not enough information is provided. A small loop of wire is placed next to a wire carrying current I. which is increasing with time. What can you say about the current induced in the loop of wire? A counterclockwise current is induced. A clockwise current is induced. No current is induced A current is induced, but it's direction cannot be determined. A square loop of wire of resistance R and side alpha is oriented with its plane perpendicular to a magnetic field B, as shown above. What must be the rate of change of the magnetic field in order to produce a current I in the loop? IR/a^2 Ia^2/R Ia/R Ra/I IRa If the magnetic field strength is increasing, the direction of the induced current will be: Around the loop clockwise Around the loop counter-clockwise into the page out of the page none of the above In a transformer, how many turns are necessary in a 110-V primary if the 24-V secondary has 100 turns? 458 240 110 22 4 A transformer consists of a 500-turn primary coil and a 2000-turn secondary coil. If the current in the secondary is 3.0 A. What is the current in the primary? 0.75 A 1.3 A 12 A 24 A 48 A In a transformer, how many turns are necessary in a 110-V primary if the 24-V secondary has 100 turns? 458 240 110 22 4

Explanation / Answer

22) N1/N2 = V1/V2 ====> N1 = 100(110/24) = 458.33 turns (option A)

23) N1/N2 = I2/I1 ======> I1 = 3(2000/500) = 12 A (option C)

24) N1/N2 = V1/V2 ====> N1 = 100(110/24) = 458.33 turns (option A)

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