Ball on a Ramp A ball is released at a height of 1 m on a frictionless 30 degree

Question

Ball on a Ramp A ball is released at a height of 1 m on a frictionless 30 degree slope. At the bottom, it turns smoothly onto a 60 degree slope going back up. What maximum vertical height does the ball reach on the right side? Magnitude of acceleration along the ramps given by (9.8 (m/s)/s)*sin(30 degree) and (9.8 (m/s)/s) sin (60 degree). Projectile Sliding Down and of Ramp A small box is released from rest at the top of the frictionless ramp shown below. Acceleration along the ramp is equal to (9.8 (m/s)/s)*sin(40 degree). How far horizontally from the end of the ramp does the box hit the floor? What is the magnitude of the box's total displacement from the end of the ramp when the box hits the floor? This is not the same question as a). What is the magnitude and direction of the box's velocity as the box contacts the ground? (Remember to show the angle theta in your diagram so that it's clear how you are measuring your angle for the final velocity.)

Explanation / Answer

As you asked multiple questions so I m bound to answer first one.

(1)

As given that the slopes are frictionless surfaces,So there is no energy loss for the ball.

maximum height reached by the body is independent of slope.

KE i = 0

at maximum height, KEf = 0

apply law of energy conservation,

PEi + KEi = PEf + KEf

PEi = PEf

m*g*h = m*g*Hmax

so, maximum height = 1 m

answer

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