The picture shows a rectangular current-carrying loop in a uniform magnetic fiel
ID: 1536913 • Letter: T
Question
The picture shows a rectangular current-carrying loop in a uniform magnetic field that is directed right. The loop is free to rotate about the axis shown as the dashed line in the top view. Select all the correct statements about this situation from the list below. As seen from the side view, the initial net torque on the loop is clockwise. As seen from the side view, the initial net torque on the loop is counterclockwise. As seen in the top view, the force from the magnetic field on the side bc of the loop is to the right As seen in the top view, the force from the magnetic field on the side bc of the loop is out of the page As seen in the top view, the force from the magnetic field on the side bc of the loop is into the page As the loop rotates, the force from the magnetic field on the side bc of the loop stays the same magnitude and direction As the loop rotates, the force from the magnetic field on the side bc of the loop changes direction As the loop rotates, the force from the magnetic field on the side bc of the loop changes magnitude As the loop rotates, the net force on the loop is always zero For the rest of this problem, use these values: the width of the loop is 22.0 cm; the length of the loop Is 70.0 cm; the current I = 3.00 amps; the field B = 2.00 T. Calculate the net torque on the loop when the loop is in the orientation shown above. Calculate the net torque on the loop when the loop, as seen from the side view, has rotated through an angle of 24.0 degrees.Explanation / Answer
(A) side view:
net torque is counterclockwise.
top view:
force on the left side ad is into the page and on right side bc is out of page.
and net force will be zero.
force on bc, direction will be same only magnitude changes.
Ans. 2nd, 4th, 8th and 9th statements are correct.
(b) F = I L B = 3 x 0.70 x 2 = 4.2 N
torque = 2( w/2 x F) = 0.22 x 4.2 = 0.924 N m
(c) torque = torque_max sin(theta)
= 0.924 x sin(90-24) = 0.844 N m
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