A thin semicircular rod has a total charge +Q uniformly distributed along it. A
ID: 1534644 • Letter: A
Question
A thin semicircular rod has a total charge +Q uniformly distributed along it. A negative point charge -Q is placed as shown. A test charge +q is placed at point C. (Point C is equidistant from -Q and from all points on the rod.) Let F_P and F_R represent the force on the test charge due to the point charge and the rod respectively. Is the magnitude of F_P greater than, less than, or equal to the magnitude of F_R? Explain how you can tell. Is the magnitude of the net force on +q greater than, less than, or equal to the magnitude of F_P? Explain. A second negative point charge -Q is placed as shown. Is the magnitude of the net electric force on +q greater than, less than, or equal to the magnitude of the net electric force on +q in part b? Explain.Explanation / Answer
Fp > Fc
if we divide whole of Q charge in small charges ....they all have electric field in same direction..... all will addup to give some Net electric field
but diffrent points of ring have electric field in differnet direction ....their vector sum will be less than above where all vectors are alined
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