Two point charges q 1=+2.70nC and q 2=6.30nC are 0.100 m apart. Point A is midwa

Question

Two point charges q1=+2.70nC and q2=6.30nC are 0.100 m apart. Point A is midway between them; point B is 0.080 m from q1 and 0.060 m from q2. (See (Figure 1) .) Take the electric potential to be zero at infinity.

Find the potential at point A.

Express your answer in volts to three significant figures.

SubmitMy AnswersGive Up

Incorrect; Try Again; 6 attempts remaining

Part B

Find the potential at point B.

Express your answer in volts to three significant figures.

SubmitMy AnswersGive Up

Part C

Find the work done by the electric field on a charge of 2.25 nC that travels from point B to point A.

Express your answer in joules to two significant figures.

SubmitMy AnswersGive Up

Explanation / Answer

a)
VA = V1A + V2A
= kq1/r1A + kq2/r2A
= 8.99*10^9 * [((2.70*10^-9)/0.05) + ((-6.30*10^-9)/0.05)]
= -647 J/C

b)
VB = V1B + V2B
= kq1/r1B + kq2/r2B
= 8.99*10^9 * [((2.70*10^-9)/0.08) + ((-6.30*10^-9)/0.06)]
= -640.5 J/C

c)
UBA = qVBA = q(VA VB)
= 2.25*10^-9*(-647.3+640.5)
= -15 nJ

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.