Two point charges are placed on the x axis.(Figure 1)The first charge, q 1 = 8.0

Question

Two point charges are placed on the x axis.(Figure 1)The first charge, q1 = 8.00 nC , is placed a distance 16.0 m from the origin along the positive x axis; the second charge, q2 = 6.00 nC , is placed a distance 9.00m from the origin along the negative x axis.

Part A

Find the electric field at the origin, point O.

Give the x and y components of the electric field as an ordered pair. Express your answer in newtons per coulomb to three significant figures. Keep in mind that an x component that points to the right is positive and a y component that points upward is positive.

Part B

Now, assume that charge q2 is negative; q2=6nC. (Figure 2) What is the net electric field at the origin, point O?

Give the x and y components of the electric field as an ordered pair. Express your answer in newtons per coulomb to three significant figures. Keep in mind that an x component that points to the right is positive and a y component that points upward is positive.

Explanation / Answer

here,

A)

q1 = 8 * 10^-9 C

q2 = 6 * 10^-9 C

xa = 16 m

xb = 9 m

net electric feild , E = k * q2/xb^2 - k * q1/xa^2

E = 9 * 10^9 * 6 * 10^-9 /9^2 - 9 * 10^9 * 8 * 10^-9 /16^2

E = 0.385 N/C

the net electric feild at the origin is 0.385 N/C in +ve x direction

B)

q1 = 8 * 10^-9 C

q2 = - 6 * 10^-9 C

xa = 16 m

xb = 9 m

net electric feild , E = - k * q2/xb^2 - k * q1/xa^2

E = - 9 * 10^9 * 6 * 10^-9 /9^2 - 9 * 10^9 * 8 * 10^-9 /16^2

E = - 0.948 N/C

the net electric feild at the origin is 0.948 N/C in -ve x direction

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