A ball is tossed from an upper-story window of a building. The ball is given an

Question

A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 9.00 m/s at an angle of 17.0 degree below the horizontal. It strikes the ground 5.00 s later. How far horizontally from the base of the building does the ball strike the ground? What is the horizontal component of the acceleration? m Find the height from which the ball was thrown. Work only with the vertical components of these quantities. This part of the problem is then a 1-dimensional free-fall example, m How long does it take the ball to reach a point 10.0 m below the level of launching? The answer to this part does not depend on your answers to parts (a) and (b).

Explanation / Answer

(a) x = u cos 17 * t
= 9 cos 17 * 5 = 43.033 m

(b) h = u * sin 17* t + 1/2 * g * t^2
= 9 sin17 * 5 + 1/2 * 9.8 *5^2 =135.65m

(c) y = u * sin 17* t + 1/2 * g * t^2
10 = 9 * sin 17 t + 4.9t^2
--> 4.9t^2 + 2.63t - 10 = 0

---> t = 1.18 s

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