Ok, I really just need to figure out Part C. TACTICS BOX 24.2 Determining the ma

Question

Ok, I really just need to figure out Part C.

TACTICS BOX 24.2 Determining the magnetic force on a moving charged particle

Note the direction of v  and B , and find the angle between them.(Figure 1)

The force is perpendicular to the plane containing v  and B . The direction of F  is given by the right-hand rule.(Figure 2)

For a negative charge, the force is in the direction opposite that predicted by the right hand rule.(Figure 3)

The magnitude of the force is given by

F=|q|vBsin or

F=|q|vB.

Part A

A vertical wire carries current in the upward direction. An electron is traveling parallel to the wire. What is the angle between the velocity of the electron and the magnetic field of the wire?

Express your answer in degrees.

90

Part B

In what direction is the force F  exerted by the magnetic field on the electron?

Part C

If the magnetic field of the wire is 2.5×104 T and the electron moves at 9.0×106 m/s , what is the magnitude F of the force exerted on the electron?

90

Explanation / Answer

Part C)

B = magnetic field = 2.5 x 10-4 T

q = charge on electron = 1.6 x 10-19 C

v = speed = 9 x 106 m/s

magnetic force is given as

F = q vB

F = (1.6 x 10-19) (9 x 106) (2.5 x 10-4)

F = 3.6 x 10-16 N

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