An electron in a certain region of space experiences a force of 8.0 times 10^-15

Question

An electron in a certain region of space experiences a force of 8.0 times 10^-15 N due East from the electric field there. Find the magnitude and direction of the electric field. What is the magnitude and direction of the electric force on an ion Mg^++ placed at the same location as the previous problem? What is the acceleration of the ion in the previous problem, given that its mass number is 24? A point charge of 30 nC is placed on the x-axis at the point x = 1. Find the x-component of the electric field E, at x = 3 and x = -2 where the coordinates are in meters. Sketch E, as a function of x. Repeat the previous problem if the point charge is - 30 nC. The next three problems refer to two point charges A and B on the x-y plane. With coordinates measured in meters. A bat (1.0) and carries charge - 5 nC. B is at (-2.0) and carries + 4 nC. Find the x-component of the electric field E, at the points (0, 0), (4, 0) and (-1, 0) and plot E, as a function of x. Find the x-coordinate of the point on the x-axis where the electric field is zero. Find the magnitude of the electric field at the point (-2.3). On the x-y plane, two equal point charges q are located at the points (a, 0) and (-a, 0). Find the magnitude of the electric field at the point (0, y). Find the value of y where the electric field is maximum. Sketch the electric field as a function of y. An electric dipole consists of a point charge -q at the point (0, a) and a point charge q at the point (0, -a). Find the electric field at the point (x, 0). Three point charges q, q, and -2q occupy three corners of a square of side a as shown. Find the magnitude and direction of the electric field at (a) the unoccupied comer, and (b) the center. Three point charges q, q, and -2q occupy the vertices of an equilateral triangle of side a. Find the electric field at the center of the triangle. A water droplet of radius 0 018 mm remains stationary in air. If the downward electric field is 300 N/C. how many excess electrons mast the droplet have?

Explanation / Answer

2) magnitude is F = q*E = 2*1.6*10^-19*E

E = Fo/qo = (8*10^-15)/(1.6*10^-19) = 5*10^4 N/C along west

then F = q*E = (2*1.6*10^-19*5*10^4) = 1.6*10^-14 N along west

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