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a secure session masteringphysics.com/myct/itemview?assignmentProblemID 73591014

ID: 1530631 • Letter: A

Question

a secure session masteringphysics.com/myct/itemview?assignmentProblemID 73591014&offset; next Phy 284 Sp17 pp10 Problem 19.45 Resources previous 4 of 4 retum to assignme Problem 19.45 Part A Three resistors having resistances of R 1.75 n Find the equivalent resistanoe of the combination. R2 2.35 n and Rs 4,65 n respectively, are connected in series to a 279 v battery that has negligible intemal Submit Part B Find the current in each resistor Answer in the order indicated. separate your answers using commas, Incorrect: Try Again, 2 attempts remaining

Explanation / Answer

the equivalent resistance of the combination would be given by:

Req = R1 + R2 + R3

Req = 1.75 + 2.35 + 4.65 = 8.75 Ohm

Hence, Req = 8.75 Ohm

b)I = V/R

I = 27.9/8.75 = 3.19 A

Its a fact that the same current flows through the resistros connected in series. So

i1 = i2 = i3 = 3.19 A

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