The equipotential surfaces surrounding a point charge are concentric spheres wit

Question

The equipotential surfaces surrounding a point charge are concentric spheres with the charge at the center. If the electric potential of two such eqipotential surfaces that surround a point charge 1.63e-8 C are 185 V and 80.0 V , what is the distance between these two surfaces? (In m) The equipotential surfaces surrounding a point charge are concentric spheres with the charge at the center. If the electric potential of two such eqipotential surfaces that surround a point charge 1.63e-8 C are 185 V and 80.0 V , what is the distance between these two surfaces? (In m)

Explanation / Answer

let the distance of the first sureface from the charge be x and that of the second charge be y.so,

kq/x=V1

or 9*10^9*1.63*10^-8/x=185

or x=0.793 m

kq/y=77

or 9*10^9*1.63*10^-8/y=80

or y=1.83375 m

so distance=y-x

=1.83375-0.793

=1.04075 m

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