The equilibrium constant, K_p, equals 3.40 at 25 degree C for the isomerization

ID: 499906 • Letter: T

Question

The equilibrium constant, K_p, equals 3.40 at 25 degree C for the isomerization reaction: cis-2-butene leftrightarrow trans-2-butene. If a flask initially contains 1.00 atm of each gas, in what direction will the system shift to reach equilibrium? a. The system is not at equilibrium and will remain in an unequilibrated state. b. It will shift left. c. The system is already at equilibrium. d. It will shift right. Identify the species that behave(s) as a base in the following chemical reaction. NH_3 (aq) + CH_3 COOH (aq) leftrightarrow CH_3 COO (aq) + NH_4^+ (aq) a. NH_4^+ (aq) b. NH_3 (aq) c. CH_3 COOH (aq) d. CH_3 COO (aq)

Explanation / Answer

Q1) Cis -2-butene <---> trans -2 -butene

Kp = 3.4 = [trans]/[cis]

When both [trans] = [cis] = 1.0 mol their partialpressures are [partial pressure = mole fractionx Ptotal]

P cis = 1/2 Ptotal

and Ptrans = 1/2 Ptotal

thus Q = 1.0

Since Q < Kp the equilibrium is not attained and goes right side.

q2)

Nh3 (aq) + Ch3COOH(aq) <----> CH3COO-(aq) + NH4+ (aq)

base acid conjugate base conjugate acid

Thus the two bases involved in the equation are

NH3(aq) and CH3COO-(aq)

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The equilibrium constant, K_p, equals 3.40 at 25 degree C for the isomerization

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