The equilibrium constant is K = [B]/[A] = 5, and the forward rate constant is k

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The equilibrium constant is K = [B]/[A] = 5, and the forward rate constant is k1 = 100 sec-1. The isomerization is now catalyzed by an enzyme. For the catalyzed reaction, the forward rate constant k1 = 10,000 sec-1. The average amount of time that the molecule spends in state A is

A B The equilibrium constant is K = [B]/[A] = 5, and the forward rate constant is k1 = 100 sec-1. The isomerization is now catalyzed by an enzyme. For the catalyzed reaction, the forward rate constant k1 = 10,000 sec-1. The average amount of time that the molecule spends in state A is

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