Print Icalculator Periodic Table Question 6 of 20 Map d Sapling Learning There a

Question

Print Icalculator Periodic Table Question 6 of 20 Map d Sapling Learning There are two identical, positively charged conducting spheres fixed in space. The spheres are 45.0 cm apart (center to center) and repel each other with an electrostatic force of FE0.0690 N. Then, a thin conducting wire connects the spheres, redistributing the charge on each sphere. When the removed the spheres still repel but with a force of F2 a 0.100 N. Using this information, find the initial charge on each sphere, q and qz if initially qh

Explanation / Answer

After the spheres are connected by thin wire

charge will be equal

F = kq^2 / r^2

0.1 = 9*10^9*q^2 / 0.45^2

q = 1.5*10^-6 C

q1 + q2 = 2q

q1 + q2 = 3*10^-6 C

F1 = kq1q2 / r^2

0.069 = 9*10^9*q1q2 / 0.45^2

q1q2 = 1.5525*10^-12

(3*10^-6 - q2 ) q2 = 1.5525*10^-12

q2^2 - 3*10^-6q2 + 1.5525*10^-12 = 0

q2 = 3*10^-6 - sqrt(9*10^-12 - 4*1.5525*10^-12) / 2

= 6.64*10^-7 C

q1 = 3*10^-6 - q2 = 2.33*10^-6 C

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