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Print Calculator Periodic Table X Incorrect R Incorrect Incorrect R Incorrect R Incorrect R Incorrect R Incorrect R Incorre Question of 18 incorrect Map Sapling Learning A particle has a rest mass of 6.95 x 10 kg and a momentum of 5.79 x 10" kg m/s. Determine the total relativistic energy of the particle Number E- 1.846 x 10 J Find the ratio of the particle's relativistic kinetic energy to its rest energy. Number 1.84 x 10 rest There is additional feedback available! View this feedback by clicking on the ncorrect bottom divider bar, Click on the divider bar again to hide the additional feedback. Close Previous ® Give Up & View solution Try Again Next Ext Explanation

Explanation / Answer

a)
E^2 = p^2c^2 + m^2c^4
=> E = sqrt[((5.79*10^-18)^2*(3*10^8)^2) + ((6.95*10^-27)^2*(3*10^8)^4)]
=> E = 1.846*10^-9 J

b)
E = K+mc^2
K = 1.846*10^-9 + 6.95*10^-27*(3*10^8)^2
=> K = 2.5*10^-9 J

Ratio = (2.5*10^-9)/(6.95*10^-27*(3*10^8)^2)
= 4

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