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x D ab-02.1172. x Wiley PLUS C Secure https:// wileyplus.com/edugen/student/mainfr.uni edugen Apps O Formatting IThe Java Complete printf for Je Gfs used 2007 Lexus ES 3 D New Tab cts used 2009 Toyota Ava Articles citations with Get You Homework t Gfs used 20o7 Toyota A WileyPLUS Halliday, Fundamentals of Physics, 10e Physics (PHYS 1303, 1304, 1307, 1308 Home Read, Study & Practice Aaaanment Open Assignment FULL SCREEN PRENTERVERSION BACK NEXT IZ Chapter Concept Chapt 21, P 072 IZ Chapter 22, Concept An electron is projected with an initial speed vi 2.20 x 105 m/s directly toward a very distant proton that is at rest, Because the proton mass is large relative to the electron mass, assume that the proton remains at rest, BY calculating the work done on the electron by the electrostatic force, determine the distance between the two particles when the electron instantaneously has speed 2vi. 002 the tolerance is +/-1 In the 3rd significant digit Click if you would like to show Work for this question Quen Question Attempts: o of 1 used SAVE roR LATER SUBMIT ANSWER 2000-2017 by John Wiley & Sons, Inc. or related mpanies. All rights reserved. Review Score Review Results by Study objective License Agreement I Erbac Poicx 20DQ 2017 lohn Busans. Inc. All Rights Reserved. A Division of lohn Sans Inc. Version 4.22. 4) c 822 PM ENG 2/2/2017 Type or speak to me 25

Explanation / Answer

Electrostatic force of attraction between electron and proton results in increasing the speed of electron

Initial KE of = 0.5 ( 9.109 x 10^-31) ( 2.20 x 10^5)^2 = 22.04 x 10^ -21 J

Final KE = 44.087 x 10^ -21 J

Electrostatic PE between two charges at "r"=- Kq^2 / r = - (9x 10^9) ( 1.602 x 10^-19)^2/r

22.04 x 10^ -21 = 44.087 x 10^ -21 - (9x 10^9) ( 1.602 x 10^-19)^2/r

- 22.04 x 10^-21 = - ( 23.09) x 10^ -19 / r

r= 1.04 x 10^ 2 m apprx

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