Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

x C Chegg Study I Guided so x D test4.pd College GPA Calculator x D equation pdf

ID: 521988 • Letter: X

Question

x C Chegg Study I Guided so x D test4.pd College GPA Calculator x D equation pdf x G Consider the following re x C Secure https:// rid-1679746 1/courses/Chem 106 Section 5 DAVIS 2016-2017 SPRG/test4.pd blackboard.olemiss.edu/bbcswebdav/pid-350131-dit-conten EE App Blackboard Learn 32A Applications By Role f Facebook pearson AA bisc 162 bdL bluedoorlabs msa Course: University of E 1/25 bisc 162 Googl Psychology Research N Netflix 4. Consider the following reaction. H2 (g) +I2 (g) 2HI (g) Thermodynamic Data at 25 oC Substance AH% mol K mol H2 (g) 131 I2 (g) 261 62.4 HI (s) 26.5 207 What is AGO for the reaction at 25 C (a) -16.0 kJ (b) -6.6 kJ (c) 116 kJ (d) 19.2 kJ 5. If AH 0 and ASO 0, then which statement is true rXn rXn 6:38 P EE O Type here to search 4/30/2017

Explanation / Answer

DeltaG° = DeltaH° - TdeltaS°

DeltaH° = deltaHf°(products) - deltaHf°(reactants)

= (2*deltaHf(HI)) - [deltaHf(H2) + deltaHf(I2)]

= (2*26.5kJ/mol) - (0 + 62.4kJ/mol)

= 53kJ/mol - 62.4kJ/mol

= -9.4kJ/mol

DeltaS° = S°(products) - S°(reactants)

= 2*S°(HI) - (S°(H2) + S°(I2))

= 2*207J/Kmol - (131J/Kmol + 261J/Kmol)

= 414J/Kmol - 392J/Kmol

= 22J/Kmol = 0.022kJ/Kmol

T = 25°C = 25+ 273 = 298K

DeltaG° = deltaH° - TdeltaS

= -9.4kJ/mol - (298K*0.022kJ/Kmol)

= -9.4kJ/mol - 6.56kJ/mol

= - 15.96kJ/mol = -16.0kJ/mol

DeltaG° = -16.0kJ/mol