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This print-out should have 9 questions. Multiple-choice questions may continue o

ID: 1525641 • Letter: T

Question

This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page - find all choices before answering. A particle moves in the xy place with constant acceleration. At time zero, the particle is at x = 4 m, y = 3.5 m, and has velocity v^rightarrow_0 = (5.5 m/s) i + (-7 m/s) j. The acceleration is given by a^rightarrow = (2 m/s^2) i + (5.5 m/s^2). What is the x component of velocity after 7 s? Answer in units of m/s. What is the y component of velocity after 7 s? Answer in units of m/s. What is the magnitude of the displacement from the origin (x = 0 m, y = 0 m) after 7 s? Answer in units of m? Neglect: Air friction. Your teacher tosses a basketball. The ball gets through the hoop (lucky shot). How long does it takes the ball to reach the hoop? Answer in units of s. What is the horizontal length l of the shot? Answer in units of m. A cat chases a mouse across a 1.1 m high table. The mouse steps out of the way, and the cat slides off the table and strikes the floor 1.4 m from the edge of the table. What was the cat's speed when it slid off the table? The acceleration of gravity is 9.81 m/s^2. Answer in units of m/s. A particle travel's horizontally between two parallel walls separated by 18.4 m. It moves toward the opposing wall at a constant rate of 6.7 m/s. Also, it has an acceleration in the direction parallel to the walls of 1.9 m/s^2,

Explanation / Answer

001. Vx = V0x + ax * t

for t = 7sec


Vx = (5.5) + (2)(7) = 19.5 m/s ........Ans

002. Vy = (-7) + (5.5 x 7) = 31.5 m/s ........Ans


003. x - x0 = V0x t + ax t^2 / 2

x - (4) = (5.5 x 7) + (2 x 7^2 / 2)

x = 91.5 m


y - 3.5 = (-7 x 7) + (5.5 x 7^2 / 2)

y = 89.25 m


displacement = sqrt(x^2 + y^2) = 127.82 m ....Ans

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