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It\'s a question related to physics2 Can you please show all the steps Thanks, C

ID: 1524973 • Letter: I

Question

It's a question related to physics2
Can you please show all the steps
Thanks, Chapter 23, Problem 002 Your answer is partially correct. Try again. An electric field given by E 1.4 i 2.0(ya 6.5) j pierces the Gaussian cube of edge length 0.440 m and positioned as shown in the figure. NThe magnitude E is in newtons per coulomb and the position x is in meters.) What is the electric flux through the (a) top face, (b) bottom face, (c) left face, and (d) back face? (e) What is the net electric flux through the cube? Gaussian surface (a) Number -2.59 Units Nem 2/C (b) Number 2.59 Units N m 2/C the tolerance is +/-2% (c) Numi Units -0.27 (d) Number o Units N m 2/C (e) Number T 0 Units This answer has no units

Explanation / Answer

a)

Flux through the top face = -2*(0.44^2+6.5)*0.44^2

= -2.59 N.m2/C

b)

for bottom face : = 2*(0^2+6.5)*0.44^2 <---------- for bottom face y = 0 .So, the 0^2 term comes

= 2.52 N.m2/C

c)

left face = -1.4*0.44^2 = -0.271 N.m2/C

d)

back face = 0

e)

net flux = flux through (left + right + front + back + top + bottom ) surfaces

= -0.271 + 0.271 + 0 + 0 - 2.59 + 2.52

= -0.07 N.m2/C

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