It\'s a question related to physics lab (The Work-Energy Theorem) experiment 6.5

Question

It's a question related to physics lab (The Work-Energy Theorem) experiment 6.5 Preliminary Assignment 1) Consider an object that moves only along the positive X axis that is subjected to a constant force pointing in the positive X direction. Show the work done by this force is the area under a Force vs. Displacement plot. 2) A cart of mass (85 1.8 ±0.1)s is configured in a setup as shown in Figure 6.4-1. The tension in the string is 0.36 N and the cart has a displacement of 40.9 cm. Determine the work done by the tension. 3) The cart in the previous example has a maximum velocity of (0.580±0.017) % . Determine the kinetic energy of the cart and compare the result with the work done on the cart in Problem 2 to confirm the Work-Energy Theorem.

Explanation / Answer

1) From the equation : Work = Force * Displacement

The area under the graph will have units of energy (Joules = N*m) This area represents the work done by the force.

2) Mass m = 851.8 g = 0.8518 Kg

Tension = T = 0.36 N

D = 40.9 cm = 0,409 m

The work done by the tension is: W = (0,36)*(0,409) = 0,147 J

3) Kinetic energy Ek = (1/2)*m*(v^2) = (1/2)*(0,8518)*(0,580)^2 = 0,143 J

Due to the uncertainty,the result can be considered approximate, So the conclusion is the energy is conserved

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