A truck covers 41.0 m in 8.60 s while smoothly slowing down to final speed of 3.

Question

A truck covers 41.0 m in 8.60 s while smoothly slowing down to final speed of 3.00 m/s. Find its original speed. The constant acceleration equation involving average velocity, 1/2 (v_xi + v_xt) might be easiest to use here. Find its acceleration. (Indicate the direction of the acceleration with the sign of your answer.) You have the correct initial velocity, so you can use the definition of acceleration as the change in velocity divided by the change in time. m/s. Colonel John P. Stapp, USAF, participated in studying whether a jet pilot could survive emergency ejection. On March 19, 1954, he rode a rocket-propelled sled that moved down a track at a speed of 632 mi/h. He and the sled were safely brought to rest in 1.40 s. Determine the negative acceleration he experienced. Determine the distance he traveled during this negative acceleration. A hockey player is standing on his skates on a frozen pond when an opposing player, moving with a uniform speed of 2.0 m/s, skates by with the puck. After 2.60 s, the first player makes up his mind to chase his opponent. If he accelerates uniformly at 0.32 m/s^2, determine each of the following.

Explanation / Answer

a) Here, 32 - u2 = 2a * 41

Also, 3 = u + a * 8.60

Thus,   (32 - u2)/(3 - u) = 2a * 41/a * 8.60

=>   9 - u2 = 28.6 - 9.53u

=> u = 6.527 m/s

Thus, original speed =   6.527 m/s

b) acceleration =   (3 - 6.527)/8.60

                             = - 0.41 m/s2

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