4. Before trip out of the well, a slug* was pumped and chased by mud with return

Question

4. Before trip out of the well, a slug* was pumped and chased by mud with returns to the pit. The pumps were stopped. The trip tank was lined up on the well. The top-drive was then disconnected and the slug allowed to fall. WELL DATA Well depth (TVD) Drill pipe capacity Mud weight 8,000 feet 0.01776 bbl/ft 9.8 ppg Heavy slug weight 11.3 ppg Slug volume in the string 20 bbls Slug: is a small volume of mud that usually 2-3 ppg more than the original mud weight. it is used to push the old mud from the pipe and be able to pull the pipe dry. Calculate the mud volume increase in the trip tank.

Explanation / Answer

For the situation given in the question it is said that volume increase per 100 bbl of mud is calculated as

100 x (new mud weight - current mud weight) / (35 - new mud weight).

in this question we are given that the new mud weight is = 11.3 ppg and the current mud weight is 9.8ppg.

But for 20 bbl , the formula is re-written as -

20 / 100 x (new mud weight - current mud weight) / (35 - new mud weight)

= 20/100x(11.3-9.8)/(35-11.3) = 20/ 6.32 = 3.16 bbl

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