A parallel plate capacitor has an electric field of 2 N/C in between its plates.

Question

A parallel plate capacitor has an electric field of 2 N/C in between its plates. If the plates are 3 cm apart, what is the potential difference from one plate to the other (also called the voltage across the capacitor)? Answer in Volts. What happens if the plates of the capacitor are moved further apart? Either the electric field strength decreases or the voltage across the capacitor increases. It depends on whether or not the charge on the capacitor is held constant or the voltage across the capacitor is held constant. The electric field strength increases. The voltage across the capacitor decreases The voltage across the capacitor increases Either the electric field strength increases or the voltage across the capacitor decreases. It depends on whether or not the charge on the capacitor is held constant or the voltage across the capacitor is held constant. The electric field strength decreases.

Explanation / Answer

We knwo that

Q = C*V

C = e0*A/d

E = V/d

Since electric field is inversely proportional to distance, So if distance is increased, electric field will decrease.

But if the charge is constant, and capacitance is decreased, because distance in increased, then voltage will have to increase.

So, Correct option will be A.

Either the electric field strength decreases or the voltage across the capacitor increases,

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