A parallel combination of a 1.33-?F capacitor and a 2.63-?F one is connected in

Question

A parallel combination of a 1.33-?F capacitor and a 2.63-?F one is connected in series to a 4.59-?F capacitor. This three-capacitor combination is connected to a 17.7-V battery. Find the charge of each capacitor. A) Find Charge of 4.59 ?F capacitor answer with units C B) Find Charge of 1.33 ?F capacitor answer with units C C) Find Charge of 2.63 ?F capacitor answer with units C I combine Cab= 1.33 +2.63 = 3.96 ?F then I get Ctot= (3.96 ?F)(4.59 ?F)/(3.96 ?F)+(4.59 ?F) = 37.63 qtot= 3.763 x 10^-5 C=qtot/Vab= (3.763x10^-5)/(2.126x10^-6) = 17.7volts 1.33 ?F charge= (1.33 x 10^-6)(17.7)= 2.4 x 10^-5 C 2.63 ?F charge= (2.63 x 10^-6)(17.7)= 4.7x10^-5 C 4.59 ?F charge = 2.4 x 10^-5 + 4.7x10^-5 = 7 x 10^-5 C but this is wrong. Can anyone figure out where I'm going wrong?

Explanation / Answer

Ctot =2.12 ?F, you are doing a calculation mistake.

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