The figure below shows an object placed a distance d_o1 from one of two convergi

Question

The figure below shows an object placed a distance d_o1 from one of two converging lenses separated by s = 1.00 m. The first lens has focal length f_1 = 21.0 cm, and the second lens has focal length f_2 = 49.0 cm. An image is formed by light passing through both lenses at a distance d_2 = 18.0 cm to the left of the second lens. (Include the sign of the value in your answers.) What is the value of d_o1 that will result in this image position? Your response differs from the correct answer by more than 10%. Double check your calculations, cm Is the final image formed by the two lenses real or virtual? real virtual What is the magnification of the final image? differs from the correct answer by more than 10%. Double check your calculations. Is the final image upright or inverted? upright inverted

Explanation / Answer

a)apply lens equation for second lens 1/f2=1/v -1/v1

here f2=49 cm,v=-18 cm v1=first image distance =?

1/49=-1/18 -1/v1

v1=-13.16 cm

applying lens equation for first lens

here f1=21cm,image distance v1=13.16 cm,object distance u=?

1/21=1/13.16 -1/u

u=35.25 cm

b)final image is virtual because of image form between lens

c)magnification m=v/u=18/35.25=0.5106 of object height

d)final image is inverted

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