A hollow aluminum cylinder has a volume of 2 500 L at 30.00 degreeC. It is compl

Question

A hollow aluminum cylinder has a volume of 2 500 L at 30.00 degreeC. It is completely filled with turpentine at the same temperature The combination is slowly waned to a new temperature of 90 00 degreeC Some of the turpentine overflows, and the remaining turpentine and the cylinder is slowly cooled back to 30.00 degreeC. How much overflows? What is the final volume of the turpentine m the cylinder? The thermal linear expansion of is 25 x 10^4 degreeC. and the volume expansion coefficient for turpentine is 9 0 x 10^4 degreC^-1.

Explanation / Answer

volume of aluminium container

volumetric expansion coeeficient = 3 * linear expansion coeeficient

Vf = Vi ( 1 + 3*alpha*dT)

Vf = 2.5 ( 1 + 3 * 25 * 10^-6 * ( 90 -30) )

Vf = 2.51125 L

volume of turpentine

Vf = Vi ( 1 + beta*dT)

Vf = 2.5 * ( 1 + 9 * 10^-4 * 60)

Vf = 2.635 L

the overflow is

Vturpentine - Valuminium = 2.635 - 2.51125 = 0.12375 L

part b )

final volume of turpentine is same as the aluminium contaner

2.51125 L

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