The square loop circuit in the diagram has sides of length 1.10 m, and each resi

Question

The square loop circuit in the diagram has sides of length 1.10 m, and each resistor is 3.60 ?. The loop is placed in a uniform 0.260 T magnetic field pointing into the page. The loop, which is hinged at each corner, is pulled as shown until the distance between points P and Q is 1.32 m. (The sides of the circuit stay the same length, but the square is "flattened" into a rhombus.)

Calculate the circuit loop's final area. (I know the loop's final Area is 1.162 m^2)

If this process takes 0.090 s, what is the average current generated in the loop? Enter your answer as positive if the current flows counterclockwise around the loop.

Explanation / Answer

Here,

L = 1.1 m

resistance , R = 3.60 ohm

magnetic field , B = 0.260 T

for distance between P and Q , PQ = 1.32 m

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let the distance between the points stretching is x

Now, for the final length of x

(x/2)^2 + (PQ/2)^2 = 1.1^2

(x/2)^2 + (1.32/2)^2 = 1.1^2

x = 0.88 m

final area , A = PQ * x

A = 0.88 * 1.32 m^2

A = 1.162 m^2

Now, for the induced current generated

induced current generated = change in magnetic flux/(time * Resistance)

induced current generated = 0.260 * (1.1^2 - 1.162)/(4 * 3.60 * 0.090)

induced current generated = 0.00962 A

the induced current generated is 9.62 mA

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