The square loop (with side length 2m) is perpendicular to a 3T magnetic field. O

Question

The square loop (with side length 2m) is perpendicular to a 3T magnetic field. Over a period of 10 s, the field increases to 5T. Describe and explain the direction of the current induced in the loop. Also, determine the average current induced in the loop and the average power dissipated by the 10 ohm resistor.

The square loop (with side length 2m) is perpendicular to a 3T magnetic field. Over a period of 10 s, the field increases to 5T. Describe and explain the direction of the current induced in the loop. Also, determine the average current induced in the loop and the average power dissipated by the 10 ohm resistor.

Explanation / Answer

when conductor is placed inside the magneticfield emf will be induced

this happens due to moving conductor or changing field

FLUX=B.A

E=-dpi/dt

area is constant AREA OF SQUARE LOOP=A=SIDE2

=4m2

=-dB/dt *A

=(5-3)/10 *4

=-0.8V direction is upwards

I=E/R

=0.8/10

=0.8/10

=0.08A

power dissipated=I2*R

=0.082*10

=0.064W

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