Shows a metal rod A-C that is forced to move with constant velocity v along two

Question

Shows a metal rod A-C that is forced to move with constant velocity v along two parallel metal rails connected with a strip of metal D-E at one end. A magnetic field of magnitude B 9.00 mT points in the direction shown perpendicular to the plane o f A-C-E-D. If the rails are separated by a distance o f 25.0 cm and the speed o f the rod is 4.80 cm/s, what is the emf that is generated as the rod moves? 12.9 mV 2.44V 6.54mV 10.8mV 3.87mV what is the current in the rod if it has a resistances of 0.025 milli- ohm? 2.97mA 4.44A 8.54mA 1.97A 9.87mV what is the rate energy is being transferred in the rod 2.58 Times 10^(-2)J 1.38 Times 10^(-5)W 8.91 Times 10^(-4)W 3.91 Times 10^(-5)j 3.80 Times 10^(-3)W

Explanation / Answer

e= BLv =0.009 T *0,25 m * 0,048 m/s =0,000108 V = 0,108 mV

I=e/R= 0,00108 V/ 0,000025 ohm = 43,2 A

P= eI= 43,2 A * 0,108 mV= 4.6 W

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