My space capsule floats at a distance of R = 1.8 time 10^11 m from the sun. I ha

Question

My space capsule floats at a distance of R = 1.8 time 10^11 m from the sun. I have a solar panel that is 5 m by 10 m. The sun releases energy as light with a power of 3.K45 times 10^26 W. What is the intensity of the sunlight at 1.8 times 10^11 m from the sun? What is the amplitude of the electric field of this light? What is the amplitude of the magnetic field of this light? If my 10 m by 5 m solar panel absorbs all light that hits it and is perfectly efficient, how much power does it supply me? What is the radiation pressure of the sunlight at my location? What force will the radiation pressure apply to my solar panel? What would be the force if it were a minor rather than a solar panel? My porthole has a window that is a polarizing filter and I am wearing polarizing sunglasses. when I tilt my head 20 degree it creates a situation as pictured. In terms of intensity of the unpolarized light, I_0, what are I_A and I_s?

Explanation / Answer

(a) y = (power) / (x^2)

where y is the intensity of light

x is distance (meters)

so, y = 3.845 x 10^(26) / 1.8 x 10^(11) = 11867.28395 watt/m^2

The intensity I,is proportional to the square of the amplitude A:

that is:

I = A²

where:
= proportionality constant

so;

11867.28395 w/(m^2) = A²
-->
A² = 11867.28395 /
-->
A = (11867.28395 / )

ignoring we get:

A = 11867.28395 = 108.937 m

(c) The formula to use is
E/B=c , where c is the speed of light = 2.99792 × 10^8 m/s

E is the amplitude of the electric eld

and B is Tte magnetic eld amplitude

so, B = 108.937 m / 2.99792 × 10^8 m/s = 3.63375 x 10^(-7) T

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