My question was originally: A car accelerates from rest at 3.00 m/s. a) How long

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My question was originally: A car accelerates from rest at 3.00 m/s. a) How long does it take the car to reach the speed of 45.0 miles/ hour? b)Another care traveling at 13.4 m/s is 20.0 m behind the first car in the left lane when the first car starts. Neglecting the lengths of the cars, when does the second car pass the first, and when does teh first car pass the second?

a.) use: Vx = V0 x+ ax t (where V0 = v sub naught) -or- same thing, VFinal = VInitial x+ ax t

solve for t to get equationVFinal / ax = t

(before plugging in your values make sure to convert 41 m/hr to m/s which comes out to be 45m/h= 20.1 m/s)

plug in your values to get: VFinal / ax = t 20.1 / 3.00 m/s2 = 6.7 s

b.) I used the equation x = x0 + v0?t +

Explanation / Answer

these steps are ok

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