My question reads: How much work does the electric field do in moving a proton f

Question

My question reads: How much work does the electric field do in moving a proton from a point with a potential f +149V to a point where it s -70V?

I understand the answer is 219eV because I got this correct, however I am wondering why it is positive and not negative -219eV since potential difference defined is Vf-Vi. The final stage of the proton was -70V and -70V -149V (initial stage) is -219 and not positive 219. I saw a solution where it is 149- -70 V which has a positive answer but 149V is the initial stage and not the final? Also, how does the answer automatically convert to eV when it started as V? Thank you for your help.

Explanation / Answer

since force is attractive

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