A hare and a tortoise compete in a race over a straight course 1.85 km long. The

Question

A hare and a tortoise compete in a race over a straight course 1.85 km long. The tortoise crawls at a speed of 0.240 m/s toward the finish line. The hare runs at a speed of 8.55 m/s toward the finish line for 1.480 km and then stops to tease the slow-moving tortoise as the tortoise eventually passes by. The hare waits for a while after the tortoise passes and then runs toward the finish line again at 8.55 m/s. Both the hare and the tortoise cross the finish line at the exact same instant. Assume both animals, when moving, move steadily at their respective speeds.

(a) How far is the tortoise from the finish line when the hare resumes the race?

? m

(b) For how long in time was the hare stationary?

? s

Explanation / Answer

here,

Length of arce course, x = 1850 m

Velocity of tortoise, vt = 0.240 m/s

velocity of hare, Vh = 8.55 m/s

Solving by using , Distance = Speed * time

Final Distance run by hare, Dh2 = (L - Dh1)
(Dh1 distance travelled by hair When stopped )

Which takes the hare, t = (L - Dh1/Vh)

In this time tortoise covers, xt = vt*t
Xt = vt/vh*(L - Dh1)
Xt = (0.240/8.55)*(1800 - 1480)
Xt = 8.982 m

Part B:
Since Tortoise is running for Whole Journey,
time of pause, tp = tortoise run time - Hase runtime
tp = L/vt - L/vh
tp = 1800/(0.240) - 1480/8.55
tp = 7326.901 s or 2.035 hrs

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