A proton follows the path shown in (Figure 1) . Its initial speed is v 0 = 2.1×1
ID: 1509873 • Letter: A
Question
A proton follows the path shown in (Figure 1) . Its initial speed is v0 = 2.1×106 m/s.
Part A
What is the proton's speed as it passes through point P?
Express your answer to two significant figures and include the appropriate units.
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Figure 1 of 1
A proton follows the path shown in (Figure 1) . Its initial speed is v0 = 2.1×106 m/s.
Part A
What is the proton's speed as it passes through point P?
Express your answer to two significant figures and include the appropriate units.
vP =SubmitMy AnswersGive Up
Provide FeedbackContinue
Figure 1 of 1
Explanation / Answer
Q = charge = -10 nC = - 10 x 10-9 C
q = charge on proton = 1.6 x 10-19 C
vf = speed at P
Using conservation of energy between point A and P
Total energy at A = Total energy at P
KE at A + Electric PE at A = KE at P + Electric PE at P
(0.5) mp vo2 + k Qq/AB = (0.5) mp vf2 + k Qq/BP
(0.5) (1.67 x 10-27) (2.1 x 106)2 + (9 x 109) (- 10 x 10-9) (1.6 x 10-19)/(0.003) = (0.5) (1.67 x 10-27) vf2 + (9 x 109) (- 10 x 10-9) (1.6 x 10-19)/(0.004)
vf = 1.72 x 106
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