Is the highlighter answer correct if not could you tell me how to solve it? Than
ID: 150634 • Letter: I
Question
Is the highlighter answer correct if not could you tell me how to solve it? Thank you so much
The image below shows a plasmid and the location of restriction enzyme sites. Which of the restrictiorn enzyme shown in the image below will produce the smallest DNA fragment when reacted with the plasmid shown below A. HindIII B. EcoRV C. Clal EcoRI 15.4/0 Clal .13.3 EcoRV HindIll EcoRV-11.3 pSS2 (15.4 kb) 40Hndll 11.95 115 4.4 4.45 Bgll EcoRV 10.76 EcoRV 9.7 5.5 9.25 6.25 Xhol Clal 9.0 BglIl 7.66 6.85 Xhol Bglll EcoRV EcoRVExplanation / Answer
No the highlighter answer is not correct. The correct answer is option D that is BglII.
REASON
Each restriction enzyme will cut the plasmid at their specific restriction sites and will produce DNA fragments accordingly.
In case of option A (HindIII) there are two restriction sites.So there will be two products (DNA fragments) and their size will be- A1. (11.5-4.0) kb=7.5kb and A2.{(15.4-11.5)+4.0}=7.9kb.
In case of option B (EcoRV) there are six restriction sites.So there will be six products (DNA fragments) and their size will be- B1. (6.85-4.45) kb=2.4kb, B2.(7.66-6.85)=0.81kb, B3. (10.76-7.66)= 3.10kb, B4. (11.3-10.76)=0.54kb, B5. (11.95-11.3)= 0.65kb, B6. {(15.4-11.95)+4.45}=7.9kb.
In case of option C (ClaI) there are two restriction sites.So there will be two products (DNA fragments) and their size will be- C1. (13.3-9.7) kb=3.6kb and C2.{(15.4-13.3)+9.7}=11.8kb.
In case of option D (BglII) there are three restriction sites.So there will be three products (DNA fragments) and their size will be- D1. (9.0-4.4) kb= 4.6kb, D2. (9.25-9.0)=0.25kb and D3.{(15.4-9.25)+4.4}=10.55kb.
So it's clear that in case of BglII the smallest DNA fragment of 0.25 kb will be produced.
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