A conducting rectangular loop of mass 0.60 kg. resistance 40 Ohm, and dimensions

Question

A conducting rectangular loop of mass 0.60 kg. resistance 40 Ohm, and dimensions a times b is allowed to fall from rest through a uniform magnetic field which is perpendicular to the plane of the loop. The loop accelerates until it reaches a terminal speed (before the upper end enters the magnetic field). Take a = 2.0 m. What is the direction of induced current in the loop? CW or CCW? What is the induced current in the loop? 3b___________What is the terminal speed of the loop? [Include a FBD] 3c__________

Explanation / Answer

Induced EMF in loop = E = B*length*v/R

Force , F = Bev = I*length*B

I = mg/length*B

I = 0.6*9.8/ 2*6

l = 0.49 A, CCW

Terminal speed be 'v'

B^2*length^2*v/R = mg

6^2*2^2*v/40 = 0.6*9.8

v = 1.64 m/s

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