A conducting bar slides without friction on two parallel horizontal rails that a

Question

A conducting bar slides without friction on two parallel horizontal rails that are 50 cm apart and connected by a wire at one end. The resistance of the bar and the rails is constant and equal to 0.10 omega . A uniform magnetic field is perpendicular to the plane of the rails. A 0.080-N force parallel to the rails is required to keep the bar moving at a constant speed of 0/.50 m/s. What is the magnitude of the magnetic field? Follow up: What happens to the force required to maintain the rails speed if a capacitor is hooked across the rails instead of a conductor?

Explanation / Answer

F = I*L*B = e/r*L*B = B*v*L/r *L*B = B^2*L^2*v/r

B^2 = F*r/L^2*v

B^2 = (0.08*0.1)/(0.5*0.5*0.5)

B = 0.25 T <--------answer

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