A U-shaped tube open to the air at both ends contains some mercury. A quantity o

Question

A U-shaped tube open to the air at both ends contains some mercury. A quantity of water is carefully poured into the left arm of the U-shaped tube until the vertical height of the water column is 20.0 cm .

Part A

What is the gauge pressure at the water-mercury interface?

1960

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Correct

Part B

Calculate the vertical distance h from the top of the mercury in the right-hand arm of the tube to the top of the water in the left-hand arm.

A U-shaped tube open to the air at both ends contains some mercury. A quantity of water is carefully poured into the left arm of the U-shaped tube until the vertical height of the water column is 20.0 cm .

Part A

What is the gauge pressure at the water-mercury interface?

1960

SubmitMy AnswersGive Up

Correct

Part B

Calculate the vertical distance h from the top of the mercury in the right-hand arm of the tube to the top of the water in the left-hand arm.

Explanation / Answer

A) gauge pressure = rho_water*g*h1

= 1000*9.8*0.2

= 1960 pa

B) let h2 is height of the mercury column in right side of the tube above water level in left side of the tube.

P_aguge = rho_mercury*g*h2

h2 = P_gauge/(rho_mercury*g)

= 1960/(13600*9.8)

= 0.0147 m

so, vertical distance h from the top of the mercury in the right-hand arm of the tube to the top of the water in the left-hand arm

delta_h = h1 - h2

= 0.2 - 0.0147

= 0.1853 m or 18.53 cm

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